9q^2-9=0

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Solution for 9q^2-9=0 equation: 



9q^2-9=0

a = 9; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·9·(-9)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$


$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*9}=\frac{-18}{18}
=-1
$


$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*9}=\frac{18}{18}
=1
$

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